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how would you solve for x? log4(x + 5) = log4 13 4 is the base
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SINCE BOTH THE BASE IS SAME SIMPLY USE (X+5) =13 AND SOLVE FOR X
thanks!
You may wish to remember that \(x > -5\).
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If \( \large \log_bx=\log_b y\), then \(\large x = y\).
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