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7^(x^3) = 49^(2x) how would you solve x? would it equal to 7^(x^3) = 7^(4x) and than (x^3) =(4x)
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Yes. Can you find all three solutions?
no , how would you solve (x^3) -x^4 = 0
1) How did you get x^4? It used to be 4x. 2) Factor. Yes, it is that same old thing.
sorry i meant (x^3) -(4x)
x(x-2)(x+2)=0
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