The area of a rectangular piece of land is 260 square meters. If the length of the land was 5 meters less and the width was 2 meters more, the shape of the land would be square.
Part A: write an equation to find the width (x) of the land would be a square. show the steps of your work.
Part B: what is the width of the land in meters? show the steps of your work.
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OpenStudy (anonymous):
@jdoe0001
OpenStudy (anonymous):
@iambatman
OpenStudy (anonymous):
@Luigi0210
OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
@Compassionate
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OpenStudy (anonymous):
@robtobey
hero (hero):
The rectangular area:
xy = 260
The square area:
(x + 2)(y - 5) = 260
Now, the thing about this is, if the area is square, then x = y, so
(x + 2)(x - 5) = 260
x^2 - 3x - 10 = 260
x^2 - 3x - 270 = 0
(x - 15)(x + 18) = 0
x - 15 = 0
x + 18 = 0
Remember, only the positive result matters.
OpenStudy (anonymous):
@Hero
so the answer for part A would be this equation : (x+2)(y-5)=260 ?
hero (hero):
The useful equation would be (x + 2)(x - 5) = 260, since we can use it to solve for x.
OpenStudy (anonymous):
@hero
thanks, but how would I find the width of the land in meters?
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hero (hero):
Solve
x - 15 = 0
OpenStudy (anonymous):
x=15
OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
thanks a lot, i fully understand how it's done now! :)
hero (hero):
@MarthaSpeaks, very well then :)
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