Question

x^2-9y^2+2x-54y-89=0

Find the center, transverse axis, foci and asymtopes of the hyperbola

Answer 1

complete the square first

Answer 2

I assume you know how to do it. It turns out the equation is equivalennt to
(x+1)^2-9 (y+3)^2-9 = 0

and so,
[(x+1)^2]/3^2 - [(y+3)^2]/1^2 = 1

Answer 3

yes? no?

Answer 4

I did (x^2x+1)-6(y^2+6y+9)=89+1-36 to complete the square

Answer 5

Where did you get the -9 from?