Question

Find the following sum.

Answer 1

\[\frac{ 12 }{ x^2-1 }+\frac{ 6 }{ x+1 }\]

Answer 2

Same thing as the previous question, just with addition :d

Answer 3

x^2-1 = (x-1)(x+1)

Answer 4

Answer: \[\frac{ 18 }{ (x+1)(x-1) }\]?

Answer 5

Is that your final answer?

Answer 6

I believe so.

Answer 7

You should've got \[\frac{ 6 }{ x-1 }\]

Answer 8

How?