Please answer
suppose you are building a rain shelter for a local park. the function y = 4 csc θ models the length y of rafter needed if the peak is 4 feet above the top of the wall. The angle θ is formed by the rafter and the top of the wall. Use a graphing claculator. find the length of the rafter need to make the roof for θ=19 degrees. Round to the nearest tenth of a foot.

Question

Please answer 
suppose you are building a rain shelter for a local park.  the function y = 4 csc θ models the length y of rafter needed if the peak is 4 feet above the top of the wall.  The angle θ is formed by the rafter and the top of the wall.  Use a graphing claculator. find the length of the rafter need to make the roof for θ=19 degrees.  Round to the nearest tenth of a foot.

anonymous · Answer

You are told the length of rafter is given by 
y=4cscθ
this is the trig relation
cscθ =1/sinθ
so 
y=4×1/sinθ


Because you are given the angle = 19 degrees you can compute it and get y.


For your graph question the confusion may arise from there being multiple maximums and minimums.

The mathematics here are to be done by inspection, so when x=2 you have maximums, and when x = -2 you have minimums.

The zeros can be seen when the graph crosses the y axis.

My advice would be to change the y scale, you are provided with an axis going from 0 to 
2π
 Divide each section by 4 and write down the new scale along the y axis
  
 *This question was asked on here before I'm not sure if this will help though

anonymous · Answer

http://assets.openstudy.com/updates/attachments/5183f809e4b09587cd393928-monki32-1367606788381-graph001.png