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Mathematics 11 Online
OpenStudy (anonymous):

Give the period of the function.

OpenStudy (anonymous):

\[y=\frac{ 1 }{ 2 } \cot x\]

OpenStudy (sidsiddhartha):

period of cotkx=pi/k

OpenStudy (anonymous):

I don't get it :/

OpenStudy (sidsiddhartha):

there are some specific periods for functions like sin(kx) has period=2*pi/k cos(kx) has=2*pi/k ans for tan(kx) and cot(kx) basic period is=(pi)/k

OpenStudy (anonymous):

so pi/k is the answer?

OpenStudy (sidsiddhartha):

in your problem k=1 so ans should be pi

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