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Mathematics 20 Online
OpenStudy (anonymous):

integrate (sinx)^1/2*cos x dx

hartnn (hartnn):

did you try substituting u = sin x ?? du =...

OpenStudy (anonymous):

just a sec iam trying

OpenStudy (anonymous):

no

hartnn (hartnn):

u = sin x du/dx = ...?

OpenStudy (anonymous):

du/dx = cos x

hartnn (hartnn):

yes so du = cos x dx what does your new integral become after substitution ??

hartnn (hartnn):

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