Question

Write the first function in terms of the second; sec x; sin x

Answer 1

@ParthKohli @iPwnBunnies

Answer 2

I may be wrong on this one.
sec x = 1/cos x
\[\cos^2 x + \sin^2 x = 1\]
Sooo,
\[\cos x = \sqrt{1 - \sin^2 x}\]

Answer 3

\[\sec x = \frac{1}{\sqrt{1-\sin^2 x}}\]

Answer 4

oh I get it thanks!