A code consists of two letters (they can be repeated) followed by one digit (0-9).

The number of possibilities is

Question

A code consists of two letters (they can be repeated) followed by one digit (0-9).

The number of possibilities is

lucaz · Answer

(# letters)*(# letters)*10

anonymous · Answer

is the sum 40 @lucaz

lucaz · Answer

it depends on how many letters you're counting

anonymous · Answer

it just sais theres the code consists of 2 letters

anonymous · Answer

$$a^b *c$$
where a is the number of options for each letter (26 in the alphabet)
b is the number of letters (you have 2)
c is the number of number digit possibilities (10)
so the answer is 6760

lucaz · Answer

let's say you're alphabet has only 5 letters, the number possibilities would be 5*5*10=250 (10 from the 0 to 9)

anonymous · Answer

simple test, if your alphabet was just x,y,z 
the 'a' value i mentioned is 3
the 'b' value is still 2
and the c is still 10
from just the letters you could have xx,xy,xz,yy,yx,yz,zz,zy,zx    (this is 9 options) 
and for each of these they have one of 10 number digits attached so for the above 9 options there are 10 options for each xx => xx0,xx1,xx2......xx9 so its (9 options * 10) = 90. the same as $$3^2 * 10$$