Question

find the values of the variables:
[15 8] [2 5] [13 3]
- =
[4x 0] [x 3y+6] [12 4y+8]

Answer 1

matrix subtraction?

Answer 2

\[\begin{bmatrix}15,&8\\4x&0\end{bmatrix}-\begin{bmatrix}2,&5\\x,&3y+6\end{bmatrix}
=\begin{bmatrix}15-2,&8-5\\4x-x,&0-(3y+6)\end{bmatrix}=\begin{bmatrix}13,&3\\12,&4y+8\end{bmatrix}\]

Answer 3

If you look at the bottom-left element you'll see that \(4x-x = 12\)
this can be solved for \(x\).


And if you look at the bottom right element you'll see \(0-(3y+6)=4y+8\)
this can be solved for \(y\).