Question

In circle X, AC is a diameter and segment ED is congruent to segment EB. What can you conclude about arc DC and arc CB? Explain.

Answer 1

I need a paragraph proof.

Answer 2

@saracha35

Answer 3

@ranga

Answer 4

I cannot help. Sorry. I have the same question and I dont know the answer

Answer 5

The "Copy Previous Drawing" is not working for me and so I will describe it in words:

Join the center of the circle X to D and B.
Triangles EDX and EBX are congruent because ED = EB (given); XD = XB = radius; and EX is shared by both triangles.
Therefore, angle DEX = angle BEX or angle DEC = angle BEC which implies that arc DC = arc CB.