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Mathematics 21 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

question?

OpenStudy (anonymous):

hartnn (hartnn):

use sin 2x = 2 sin x cos x

OpenStudy (anonymous):

Then factor the cosine out.

OpenStudy (anonymous):

nevermind my last answer

hartnn (hartnn):

2 sin x cos x +cos x = 0 factoring out cos x because it is common in both the terms cos x (2 sin x+1) = 0 cos x = 0 find the values of x 2 sin x +1 = 0 , find sin x , then other values of x

OpenStudy (anonymous):

@hartnn cos x = 0 then the answers are 1 and -1 right?

OpenStudy (anonymous):

its zero and 2pi/3 right?

hartnn (hartnn):

nopes, x is an angle, will be in radians cos x = 0 x = pi/2 , 3pi/2

hartnn (hartnn):

sin x = 0 gives x = 0

hartnn (hartnn):

infact, sin x =0, gives x=0,2pi

hartnn (hartnn):

but we here need 2 sin x +1 =0 sin x = -1/2 for which 2 angles ?

OpenStudy (anonymous):

7pi/6 and 11pi/6?

hartnn (hartnn):

correct! so your angles are pi/2, 3pi/2,7pi/6 , 11pi/6 :)

OpenStudy (anonymous):

when i write my answer should i specify that the first two are cosine and next 2 are sine? or just list all four?

hartnn (hartnn):

just list them :)

OpenStudy (anonymous):

thanks

hartnn (hartnn):

welcome ^_^

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