help
question?
use sin 2x = 2 sin x cos x
Then factor the cosine out.
nevermind my last answer
2 sin x cos x +cos x = 0 factoring out cos x because it is common in both the terms cos x (2 sin x+1) = 0 cos x = 0 find the values of x 2 sin x +1 = 0 , find sin x , then other values of x
@hartnn cos x = 0 then the answers are 1 and -1 right?
its zero and 2pi/3 right?
nopes, x is an angle, will be in radians cos x = 0 x = pi/2 , 3pi/2
sin x = 0 gives x = 0
infact, sin x =0, gives x=0,2pi
but we here need 2 sin x +1 =0 sin x = -1/2 for which 2 angles ?
7pi/6 and 11pi/6?
correct! so your angles are pi/2, 3pi/2,7pi/6 , 11pi/6 :)
when i write my answer should i specify that the first two are cosine and next 2 are sine? or just list all four?
just list them :)
thanks
welcome ^_^
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