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Mathematics 19 Online
OpenStudy (anonymous):

cos^2(x)=1/2

OpenStudy (anonymous):

noted

OpenStudy (anonymous):

ok i guess you have to solve for \(x\)right? start with \[\cos(x)=\pm\frac{1}{\sqrt2}\] or to make them more clear, maybe \[\cos(x)=\frac{\sqrt2}{2}\] or \[\cos(x)=-\frac{\sqrt2}{2}\]

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