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OpenStudy (anonymous):
DIFFENTIATE ln^3(x)
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OpenStudy (akashdeepdeb):
y = ln^3 x = (ln x )^3 Use chain rule now. y' = 3 * ln^2 x . d (ln x )/dx = 3 * ln^2 x . 1/x = (3 * ln^2 x)/x
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