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Physics 7 Online
OpenStudy (loser66):

I need help

OpenStudy (loser66):

OpenStudy (loser66):

@eashmore

OpenStudy (anonymous):

Do all the bulbs have the same resistance (R) value?

OpenStudy (loser66):

Yes, they do

OpenStudy (anonymous):

What do we know about resistors in series?

OpenStudy (loser66):

in series, \(R_eq= \sum R\)

OpenStudy (anonymous):

What about their currents? If R1 and R2 are in series in a simple circuit, what is the current through each?

OpenStudy (loser66):

the same

OpenStudy (anonymous):

Correct.

OpenStudy (anonymous):

In this problem... The total current through the top two bulbs in parallel equals the current through the bottom three bulbs.

OpenStudy (loser66):

Yes.

OpenStudy (anonymous):

Let's work through this problem mathematically. First, find the equivalent resistance of ALL five bulbs.

OpenStudy (loser66):

\[R_{AB}= \dfrac{R_a*R_B}{R_A+R_B}=\dfrac{R}{2}\]

OpenStudy (anonymous):

While doing this, note the equivalent resistance of the following three groupings. |dw:1399169788890:dw|

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