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solve for x: a right triangle has a short leg of 6 and a hypotenuse of radical 41. (PLEASE HELP!)
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where is x involved here??
well, I said that the short leg is 6 and the hypotenuse is radical 41. which leaves only one leg for x to be.
Use the Pythagorean relation, x^2 + 6^2 = 41^2
I'll try it, thanks!
Anytym..!!
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