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idk ummm i think it's B
Well notice how we have f(x) and they want to know f(6) well what changed? The (x) got replaced with (6) so that's all we need to do in our function as well...replace ever 'x' we see with a '6' and see what it equals \[\large f(x) = \frac{2x + 6}{x + 2} \] \[\large f(6) = \frac{2(6) + 6}{(6) + 2}\] \[\large f(6) = \frac{12 + 6}{6 + 2} = \space? \]
I GOT 18/4
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