Question

The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle?

A. In the exterior of the circle
B. At the center of the circle
C. On the circle
D. In the interior of the circle

Answer 1

plug the point into (x-8)^2+(y-5)^2

Answer 2

@myininaya ok i got (5-8)^2+(1-5)^2

Answer 3

simplify

Answer 4

how do i do that?

Answer 5

5-8=?

Answer 6

-3

Answer 7

good
what is 1-5?

Answer 8

-5

Answer 9

you mean -4?
\[(-3)^2+(-4)^2\]

Answer 10

oh yeah

Answer 11

now what is the square of (-3)?

Answer 12

-6?

Answer 13

what is (-3)(-3)?

Answer 14

9

Answer 15

yes 9

good
what is (-4)^2?

Answer 16

16

Answer 17

In the interior of the circle

Answer 18

ok so what is 16+9

Answer 19

25

Answer 20

is 25<81?

Answer 21

yes

Answer 22

so it is in the interior

Answer 23

Ohhh ok thanks so much!!! You really helped :)

Answer 24

if we got something > then we would say the exterior
if we had got something = to then we would say on the circle

Answer 25

got it! thank you!

Answer 26

and the center of the circle is definitely not (5,1) since it is (8,5)

Answer 27

@myininaya can you help with one more? i'll ask a new question :)

Answer 28

just one more
then i must get ready for tonight's event