Question

Solve for x....Please help!!

Answer 1

whats the question?

Answer 2

\[2^x(2^x+2)=\frac{2 ^x+2^3x{} }{ 2^-x }\]

Answer 3

and the x should be 2^(3x) and 2^(-x)

Answer 4

\[\large 2^x(2^x+2)=\frac{2 ^x+2^{3x} }{ 2^{-x }}\]\[\large 2^{-x} 2^x(2^x+2) = 2 ^x+2^{3x}\]\[\large 2^x+2 = 2 ^x+2^{3x}\]\[ \large 2 =2^{3x} = (2^3)^x = 8^x\]\[\large x = log_8(2) = \frac{ 1 }{ 3 }\]