Question

Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt is saving up for a used car that costs $4200.

A. Look at the algebraic equations below. Which equation can be solved to find out the number of deposits Matt needs to accumulate more than $4200? (1 point)

•200x + 300 > 4200.
•300x + 200 > 4200.
•200x + 300 < 4200.
•300x + 200 < 4200.
B. Solve, using algebraic transformations, the equation that you chose for Part A.

C. How many deposits does Matt need to accumulate more than $4200? Remember labels.

Answer 1

@hartnn

Answer 2

hartnn is offline

Answer 3

ok can u help @MeganChase

Answer 4

um...give me a second to figure it out. dont be dissapointed if i cant ok?

Answer 5

sorry i have to go eat. bbl

Answer 6

:(

Answer 7

Matt has already $200 in the bank

to those $200 in the bank, each month, he's adding up $300

so 1st month his amount will be
200 + 300
2nd month
200 + 300 + 300
3rd month
200 + 300 + 300 + 300

and so on
notice that \(\begin{array}{llll}
200 + 300\implies &200+300({\color{red}{ 1}})\\
200 + 300 + 300\implies &200+300({\color{red}{ 2}})\\
200 + 300 + 300 + 300\implies &200+300({\color{red}{ 3}})
\end{array}\)

any ideas what equation might be A?

Answer 8

@jdoe0001 can u number it like A B C pleez

Answer 9

\(\begin{array}{llll}
month&amount\\
\hline\\
{\color{red}{ 1}}&200 + 300\implies &200+300({\color{red}{ 1}})\\
{\color{red}{ 2}}&200 + 300 + 300\implies &200+300({\color{red}{ 2}})\\
{\color{red}{ 3}}&200 + 300 + 300 + 300\implies &200+300({\color{red}{ 3}})\\
{\color{red}{ x}}&\qquad \implies &200+300({\color{red}{ x}})
\end{array}\)
so that amount has to be $4,200 or more, because the car is $4,200, so the dealer is not going to sell it for less, so Matt has to have at least that much

so one can say the amount he needs to have be \(\bf 200+300({\color{red}{ x}})\qquad {\color{red}{ x}}=\textit{amount of months depositing 300 each time}\)

Answer 10

and that quantity, has to be GREATER than $4,200