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how does 2cos5xsin5x turn into/equal sin10x?
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\(\sin(2*x)=2\sin(x)cos(x)\) so \(\sin(2*(5x))=2\sin(5x)\cos(5x)\) i.e. \(\sin(10x)=2\sin(5x)\cos(5x)\)
ah... the application of the double angle formula confused me. thank you
i didn't know how to use the double angle formula
think of it anytime you have sin cosin next to each other for identities anyway....
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