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(i square root 3)^2
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|dw:1399075875695:dw|
if we have (a*b)^2 = a^2 * b^2 so (i * root(3))^2 = ---------------?
So (i * (sqrt3))^2 = i^2 * (sqrt3)^2 okay ?
Welp, The square root and square cancel out, you have i3, and i3 is complex so that would be -3 :P
|dw:1399076106817:dw|
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Correct !! , what would be the next step ?
im not sure how to do the exponents when theres a square root
|dw:1399076289452:dw|
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