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Given quadrilateral ABCD, where AB || CD, ∠ABC ≅ ∠CDA, and a diagonal AC. Which method can be used to prove TriangleABC ≅ TriangleCDA? f Angle-Angle-Side (AAS) g Side-Side-Angle (SSA) h Side-Angle-Side (SAS) j Side-Side-Side (SSS) Questions regarding this site should be directed to Steve Gagnon. Please include this quest
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Easiest thing to do is draw it, so let's sketch it out.
|dw:1399081205456:dw|
And then, because both triangles have the same angle and the two sides are parallel, ad and bc have to be congruent
|dw:1399081369933:dw|
Then, because AC is shared by both triangles, we know it's the same for both, we now have two pairs congruent side and 1 congruent set of angles.|dw:1399081481066:dw| So side angle side I think
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