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OpenStudy (anonymous):
suppose A is a non-empty set. Is x ∈ A -> x ∈ A U B for all B true?
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OpenStudy (zzr0ck3r):
Yes
OpenStudy (anonymous):
okie :)
OpenStudy (zzr0ck3r):
not much of a proof ... \(x\in A \implies x\in A\cup B \ \ \ \ \ _\blacksquare\)
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