Question

Assume the variable is positive, and find the following root.

Answer 1

\[\sqrt[3]{27x^15}\]
Is to the power of 15 but it doesnt wanna go up there @Miracrown @hartnn

Answer 2

*it's

Answer 3

\(\Large \sqrt[3]{27x^{15}}\)

Answer 4

yes!

Answer 5

so,
\(\sqrt[3]{27x^15} = \sqrt[3]{27} \times \sqrt[3]{x^{15}}\)

whats cube root of 27 ?

Answer 6

3?

Answer 7

yes
and