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Find x in the following right triangle, where a = 4. (Round your answer to one decimal place.)
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Picture:
same pythagoras theorem
\(x^2 = a^2+a^2\)
\(x^2= 4^2+4^2\)
32
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thats x^2 not x
\[x=\sqrt{32}\]
5.6, but if I round it, it's 5.7 right?
5.656 yes, it'd be 5.7 :)
Thanks
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welcome ^_^
dragon ballz kinda is lame
infact it is lame not kinda lame
-.-- get tf on my post disrespecting DBZ
its aint ur website and ur nothe tfing creator of dragon balz
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but it's my post & used to be one of my fav cartoons, so BYEEEEE !
knock it off, both of you
just bcuz its ur fav cartoon thts y u told bye lol rofl
okay @hartnn just kinda got bored no offence cook
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