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Find cos θ if sin θ = -5/13 and tan θ > 0.
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@hartnn
@sidsiddhartha
\(\cos^2 \theta = 1- \sin^2 \theta \)
i got -13/5
how ?
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for the equation
\(\cos \theta = \sqrt{1-(-5/13)^2} \)
\(\cos \theta = \sqrt {144/169} = 12/13\)
and since tan theta is positive both sin and cos would be negative so final answer would be cos theta = -12/13
ohh!!!
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