Question

factor 4b^2-7b-28b+49 by grouping

Answer 1

first rearrange it so its like this:\[4b^2-28b-7b+49\]
then factor each group:
\[4b(b-7)-7(b-7)\]
then:\[(4b-7)(b-7)\]

Answer 2

Thanks! I had already figured this one out, though, but it took me a long time...