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Mathematics
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An executive committee of 13 members consists of 7 men and 6 women. What are the odds all five selected are women?
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Please help me solve!
odds of first one selected being a woman = 6/13 that leaves 7 men and 5 women odds of getting another woman = 5/12 continue this another 3 times to get 5 women since these events are independent we get our answer by multiplication of the 5 fractions
so it is 6/13 times 5/12 times 4/11 times 3/10 times 2/9?
yes
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