Question

Does anyone know how to integrate (1-(sinx)^3)/(sinx)^2? I already tried a few things, but everytime i get stuck...

Answer 1

i think u can work on this
\[\large \int\frac{1-\sin^3x}{\sin^2x}\,dx=
\int\left(\frac{1}{\sin^2x}-\frac{\sin^3x}{\sin^2x}\right)\,dx \]

Answer 2

\[\large =\int\left(\frac{1}{\sin^2x}-\sin x\right)\,dx \]

Answer 3

u can use tables for this