Question

perpendicular to y = 7x + 1 and passing at a distance sqrt(2) from (4,-2)

Answer 1

wassat?

Answer 2

can u answer this ?

Answer 3

I don't see a question per se

Answer 4

perpendicular to y = 7x + 1 and passing at a distance from (4,-2)

Answer 5

hmm perpendicular? who?

Answer 6

our topic is all about straight line

Answer 7

can u answer

Answer 8

well, what do you think is the slope of " y = 7x + 1 " ?

Answer 9

thats what im asking you

Answer 10

slope of given line=7
slope of line perpendicular to given line=-1/7
eq. of reqd. line is \[y=-\frac{ 1 }{ 7}x+c,7y=-x+7c,x+7y-7c=0\]
find perpendicular distance and put=sqrt 2
find c,put the value of c and get two equations.