Question

Mia is three years older than twice her sister Brooke’s age. The sum of their ages is less than 30. What is the greatest age Brooke could be?

A. 7
B. 8
C. 10
D. 9

Answer 1

Mia = 3 + 2B
Brooke = B

Answer 2

So, 3+3B can't be greater than 30

Answer 3

So, the answer would be D

Answer 4

I think the answer will be B. 8
because the equation will look like this, say M=Mia's age and x = Brook's age
M + x < 30
(3+2x) + x < 30
3 + 3x < 30
3(1+x) < 30
1+x < 10
x<9
so that will be 8, x cannot equal 9 but has to be less than 9