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Checking my answer lim x->inf ((4x-9)^1/2)/(x+3). Is it equal to 0?
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yep, its 0 ! :)
cool ^_^ and it's because on the top it's power to 1/2 and bottom power to 1?
thats correct. a more methodical way to do this is to divide numerator and denominator by 'x' so that you get terms like 1/x, 1/x^2, ...and so on, and since x approaches infinity, all those terms will approach 0
ah ok, I'll remember that, thanks!
welcome ^_^
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umm
if I divide (4x-9)^1/2 by x, what do I get?
|dw:1399191333993:dw|
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