PLEASE HELP WILL GIVE MEDAL!!!!!!!!!!!!!!!!!!!!!
the points (4,-2) and (-2,8) lie on the line Ax-2 By=28. what is the value of A?
since the given points lie on the line, they must satisfy the line
plug them get two equations
how?
Ax-2 By=28 plugin the first point : (4, -2) A(4) - 2B(-2) = 28 4A + 4B = 28 A + B = 7 ---------------------(1)
similarly plugin the other point, and see if u can get another equation ?
okay... 2x+16B=28?
try again
wait i did it wrong, its 2A+16B=28
correct?
Ax-2 By=28 plugin the first point : (-2, 8) A(-2) -2B(8) = 28 -2A -16B = 28 A + 8B = -14 --------------------(2)
^^
but the point was(2, -8)
@shubhamsrg can u help me
ur back!
@ganeshie8 this wasn't the first point: "plugin the first point : (-2, 8)"
ahh typo, scratch that.. see if below looks okay : Ax-2 By=28 plugin the SECOND point : (-2, 8) A(-2) -2B(8) = 28 -2A -16B = 28 A + 8B = -14 --------------------(2)
your two equations are : A + B = 7 ---------------------(1) A + 8B = -14 --------------------(2)
the second point was (2,-8)
then work the second equation again
but the original question says : ``` the points (4,-2) and (-2,8) lie on the line Ax-2 By=28. what is the value of A? ```
was there a typo ?
yes im stupid, im so sorry, i meant to say (2,-8)
alright. so 2A+16B=28
Looks good !
A+8B=14
Now i get it!!
so your equations are : A + B = 7 ---------------------(1) A+8B=14 ---------------------(2)
yes
eliminate B since you want the value of A
may be solve for B from first equation, then substitute it in 2nd equation
so you would multiply 8(A+B=7)
negative 8 actually
okay then subtract ..... A=6!
not 6 factorial, just 6
thanks @ganeshie8
A = 6 is \(\large \color{red}{\checkmark }\) http://www.wolframalpha.com/input/?i=A+%2B+B+%3D+7%2C+A%2B8B%3D14+
really appreciated ur help
u wlc :)
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