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help i will give a medal!! two consecutive odd integers for 236. whats the smallest integer?
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First some terminology, two consecutive odd integers are two integers that are right after the other with a difference of 2 so x + (x + 2) = 236 Use the distributive property: 2x + 2 = 236 and subtract 2 from both sides and get 2x = 234 so smallest integer is 117
It should be the additive property because x and x is 2x
thank you again haha your a lot of help
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