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Linear Algebra 15 Online
OpenStudy (loser66):

find nullity of A =\(\left [\begin{matrix}6&0&2\\0&6&0\\0&0&4\end{matrix}\right]\) Please, help

OpenStudy (nipunmalhotra93):

by dimension theorem, you have 3=nullityA+rankA. Now, clearly this matrix is invertible. Which means that its rank is 3. So, nullityA=0

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