Question

Use mathematical induction to prove the statement is true for all positive integers n.

6 + 12 + 18 + ... + 6n = 3n(n + 1)

Answer 1

@agent0smith
i have this so far:
6+12+... 6k=3n(+1)
6+12+...+ 6k+ 6(k+1)=[6+12+...+6k]+6(k+1)
3k(k+1)+6(k+1)
3(k+1)(k+2)
3(k+1)(k+1)+1