Question

let sinA = 3/5 in QI find cosA and tanA

Answer 1

\[\cos A=\sqrt{1-\sin^2 A}=\sqrt{1-(3/5)^2}\]
\[\tan A=\frac{\sin A}{\cos A}\]

Answer 2

Q1 = quadrant 1? as in first quadrant

Answer 3

I would just draw the triangle and use the Pythagorean theorem

Answer 4

that would be 16 and the square root is 4