Question

Find all solutions in the interval [0, 2π).

tan x + sec x = 1

Answer 1

x = 0

x = pi/4

No solution

x = 5pi/4

Answer 2

-1+tanx+secx=0
y = tan(x/2), sin(x) = 2y/(y^2+1), cosx = (1-y^2/y^2+1)

Making it into a rational equations -2y/(y-1) = 0

y = 0

x/2 = pin

\[x=2 \pi n\ for \ n \in Z\]

Answer 3

I got pi/4 @iambatman

Answer 4

@dumbcow

Answer 5

either that or 5pi/4

Answer 6

x = 0, 2pi, 4pi etc

since domain is (0,2pi) , answer must be 0