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Please help me!!!! Find the area under the curve y= 3/x on the interval [1,2]
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you are being asked to integrate a log function so its \[A = \int\limits_{1}^{2} \frac{3}{x} ..dx\] which can be written as \[A = 3 \times \int\limits_{1}^{2} \frac{1}{x}..dx\] hope it helps
A = ∫3/x dx-----------limits 1 to 2
Okay so I just have to integrate that problem and I will have the answer???
yeah
awesome just one minute I am going to integrate it.
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so what's ur answer?
Okay I got... \[\int\limits_{1}^{2} 1/x dx = \ln(2) =3\ln(2)\]
I don't know if I did that right.
|dw:1399407628644:dw|
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