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X^2-y=3 x-y=-3 solution set HELP PLEASE! I need a answer not a explanation!
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Look at the question again, I typed it incorrectly the first time
Now, expand and solve the quadratic equation.
I need a little more explanation please. This time with the equation X^2-y=3 x-y=-3
I think you switched things up on me. isolate y in both equations.
x^2 - 3 = y x + 3 = y Then set y = y x^2 - 3 = x + 3 Then setup a quadratic equation.
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so it would be x^2-3=o and x+3=0?
No, you skipped a step
You have to put the equation x^2 - 3 = x + 3 in the form ax^2 + bx + c = 0
how do I know what goes where?
I am just now learning this stuff
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