Question

From a standard deck of cards, what is the probability that you draw a red card, replace it and then draw a heart?

Answer 1

Someone please help

Answer 2

Here, I don't know if this helps much, But I found this answer offline:

In a deck there a 52 cards with 4 suits(hearts,spades,diamonds and clovers). 2 suits are red while the other 2 are black. And there are 4 cards for each number.(ace,jack.queen etc.)And remember an ace isnt considered a face card.

1) there are 2 red kings in any given deck so probability is 2/52=1/26

2)since there are 4 cards of each
you multiply 4*3=12
probability is 12/52=3/13

3)I have no idea what a fade is.

4)Remember that there are 4 suits? Each suit has 13 cards.
So as there are 2 suits probability is 13*2/52=26/52=1/2

5)There are 26 black cards,and they contain 6 face cards. And there are 26 red cards which contain only 2 red aces. so add both 8/52=2/13

6)In a deck there are 12 face cards (king, queen, and jack) and 13 cards of spades
3 face cards are already in spades so subtract 3.
(9+13)/52=22/52=11/26

Answer 3

I only have answer choices of 1/8 or 3/8 or 3/4 or 2

Answer 4

.... Err.. @iambatman do you know how to do this?

Answer 5

Do I have to read all that :c

Answer 6

No, No you don't batman.

Answer 7

please someone help me

Answer 8

There are 26 red cards (13 heart + 13 diamonds) out of 52 total.

So P(Red) = 26/52 = 1/2

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There are 13 heart cards (A,2-10, J,Q,K) out of 52 total

P(Heart) = 13/52 = 1/4

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Since each event is independent (the card drawn first is replaced), this means

P(Red & Heart) = P(Red)*P(Heart)

P(Red & Heart) = (1/2)*(1/4)

P(Red & Heart) = (1*1)/(2*4)

P(Red & Heart) = 1/8