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Just need someone to check my answer please Simplify (1 − cos x)(1 + cos x). 1 cos^2 x <------ sin^2 x tan^2 x
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that is incorrect
\(1-\cos^{2}x\)
when you used the difference of squares formula, what did you get? (1 − cos x)(1 + cos x) = ( )^2 - ( )^2 what goes in each parenthesis?
then use the pythagorean identity \(\cos^{2}x + \sin^{2}x = 1\)
it is 1 isn't it? because it is cos x^2 -cosx^2
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\(cos x^2 -cosx^2 = 0\)
nope... and you may want to use the equation editor to write more clearly.
so what is the answer and how do i get to it?
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