solve 12^x-2= 20 (use log)
"x-2" is the exponent ?
yes
\(\LARGE\color{blue}{ \bf 12^{x-2}= 20 }\) \(\LARGE\color{blue}{ \bf log~12^{x-2}= log~20 }\) \(\LARGE\color{blue}{ \bf (x-2) log~12= log~20 }\) \(\LARGE\color{blue}{ \bf (x-2) = log~20/log~12 }\) \(\LARGE\color{blue}{ \bf x = 2+log~20/log~12 }\) \(\LARGE\color{blue}{ \bf x = 2+log_{12}~20 }\) can you do it from here ?
no lol
i tried
you can use the calculator to solve \(\LARGE\color{blue}{ \bf log_{12}~20 }\) and then finish off by adding the right side, http://www.1728.org/logrithm.htm or do you need exact answer in terms of log ?
solve for x i need it rounded to the nearest ten thousandth
thats wrong wolfram
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