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Exponential Equations Solve 12^x-2=20 Round to the nearest ten-thousandth x=__________
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is it \[\large 12^{x-2}=20\]?
yes
use the change of base formula \[\large b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]
so what would the answer be?
whatever you get when you replace \(A\) by \(20\), \(b\) by \(12\) and \(x\)by \(x-2\) in the above change of base formula you will need a calculator to compute the number as a decimal
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ok i will plug it in, thank you
do you happen to have a calculator, im using a pelletty free one on the computer.
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