Question

Solve 6^5x = 20
Round to the nearest ten-thousandth
x=_______

Answer 1

satellite you are a bro...

Answer 2

\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\] by the change of base formula, which is what you need here

Answer 3

can you plug it in for me?

Answer 4

you get in one step
\[5x=\frac{\ln(20)}{\ln(6)}\] making
\[x=\frac{\ln(20)}{5\ln(6)}\] and a calculator