Question

factor

Answer 1

\[G \frac{ Mm }{ x^2 }-G \frac{ Lm }{(C- x)^2 }\]

Answer 2

factor after taking common terms out..

Answer 3

IDK how

Answer 4

G G G G G G G

Answer 5

haha

Answer 6

Common term :d

Answer 7

x and m too!

Answer 8

m is also common

Answer 9

Was going to say m haha.

Answer 10

x? :O

Answer 11

you want to factor for solving x ?

Answer 12

if so, u may use quadratic formula after pulling out GCF

Answer 13

\[G \frac{ Mm }{ x^2 }-G \frac{ Lm }{(C- x)^2 } = \dfrac{Gm}{x^2(C-x)^2}\left(M(C-x)^2 - x^2L \right)\]

Answer 14

oh save the quadratic formula,
we use the identity : \(a^2 - b^2 = (a+b)(a-b)\)

Answer 15

\[G \frac{ Mm }{ x^2 }-G \frac{ Lm }{(C- x)^2 } = \dfrac{Gm}{x^2(C-x)^2}\left(M(C-x)^2 - x^2L \right) \\ = \dfrac{Gm}{x^2(C-x)^2}\left( \sqrt{M}(C-x) + x\sqrt{L}\right)\left( \sqrt{M}(C-x) - x\sqrt{L} \right)\]