Question

Hey plz can some1 help me find the slant height, height, and area face (area of face i guess) of an octahedron?? Please its urgent really urgent

Answer 1

@mathslover

Answer 2

@nikato do you know this?

Answer 3

It has an edge of 6.8

Answer 4

oh and i need base area too :/

Answer 5

Elisa - Please refer to this link - http://www.math.ubc.ca/~cass/courses/m308/projects/cchang/webpages/octahedron.html

Answer 6

i couldnt really comprehend it, but if you cant help me with this can you clarify an answer for me? i did base area for a regular tetrahedron with an edge of 10.4 and then i ended up getting 27.04sqrt3

Answer 7

some1 else helped me but i doubt that answer...

Answer 8

you're working on octahedron or tetrahedron ? which question you're stuck at ?

Answer 9

Most importantly i need the octahedron stuff which is slant height, base area, height, and area of face , and it has an edge of 6.8

Answer 10

total Area of octahedron = \(\large 2 \sqrt{3}~ s^2\)
\(\large s = 6.8\)

Answer 11

since an octahedron has 8 faces, dividing the total Area by 8 gives you `area of a single face`

Answer 12

i got 20.02

Answer 13

should be right if your calculation is correct

Answer 14

^thats the area of one face

Answer 15

yeap and how do i get slant height, or height, or base area now ? :)

Answer 16

` slant height, base area, height`

can you define these ?

Answer 17

tbh, idk what they refer to... if you can tell me what they're we can find htem

Answer 18

that edge is a side of length 6.8,
can u show me what `slant height` and `height` are on the figure ?

Answer 19

i think im not sure about the slant height

Answer 20

easy :

slant height = height of equilateral triangle of side 6.8