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if cos theta =2/3 find 2sec^2 theta + tan^2theta-7
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You will need to use the following pieces of information: \[\sin^2\theta + \cos^2\theta = 1\] \[\tan \theta = \frac{\sin \theta}{\cos \theta}\] \[\sec \theta = \frac{1}{\cos \theta}\]
since all of these things are either sin or cos, and we already have cos, we should find sin first using the first formula.
see if you can make any progress with that idea. :)
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